Use of Parallax to Calculate Mars' Distance from Earth
and Use of Kepler's Third Law to Calculate Earth's Distance from Sun
This lab has the following objectives:
-
to let you repeat the experiment by which Jean-Dominique Cassini and his
assistants, Jean Richer and Jean Picard, estimated the distance between Earth
and Mars using parallax
-
to have you apply Johannes Kepler's Third Law to see how the research team
used the Earth-Mars distance to estimate the Earth-Sun distance
-
to have you back-engineer what the actual angular distance between Earth and
Mars must have been on that October 1st, 1672, had Cassini's team had modern
equipment, given the contemporary figure for the Astronomical Unit
-
to give you an appreciation for the intellectual achievement of the Cassini
team and for their meticulousness in the face of instrumental limitations
Background
Using Tycho Brahe's database, Johannes Kepler worked out three laws of
planetary motion:
- planets follow ellipical orbits, with the sun at one of the two foci of
the ellipses
- a line drawn from a planet to the sun sweeps out equal areas in equal
times, so a planet has to speed up at perihelion to compensate for the shorter
distance between it and the sun and slow down at aphelion to offset the longer
distance
- the cube of the semi-major axis of a planet's orbit is directly
proportional to the square of its orbital period, so, if you consider two
planets in orbit around the sun, the ratio of the cubes is the same as the
ratio of the squares:
(where P stands for orbital Period and R stands for the semi-major Radius)
Using these laws, scientists had worked out relative distances among the
various planets then known in the solar system, but they had no idea what the
absolute distances were. They knew Jupiter, for example, was out there about
five times as far from the sun as the earth was, but they didn't know what
that meant since they didn't know how far Earth was from the sun.
That was the problem Cassini took on. As observations improved rapidly with
better instrumentation, better predictions of the planets' positions could be
made. It was known that Mars and Earth would be in opposition (Mars, Earth,
and the sun in a straight line, with Mars and Earth on the same side of the
sun) in September and October of 1672. This meant outstanding observation
opportunities, because the two planets would be relatively close together.
English astronomer John Flamsteed had predicted that Mars would pass in front
of a particular star in the constellation Aquarius (the middle Psi star) on
the first of October, 1672.
The prediction galvanized the astronomy community, and Cassini decided to
exploit this once in a lifetime opportunity. With the Earth and Mars in a
straight line from the sun, it would be possible to work out the Mars-Earth
distance and, applying Kepler's Third Law, the Earth-Sun distance as a
function of the Mars-Earth distance.
He sent a friend and collaborator, Jean Richer, down to a town called Cayenne
in French Guiana on the north coast of South America. The town was 7,089 km
away, which would provide a long baseline to do parallax-based observations.
The baseline would not be the great circle distance of 7,089 km, though, but
the chord of that distance (the distance of a tunnel going straight through
the earth from Paris to Cayenne). The chord baseline distance would be
roughly 6,700 km.
Richer was to make precise recordings of Mars' position at
midnight on the appointed evening with respect to the Psi stars in Aquarius.
At midnight that evening, Cassini and another collaborator, Jean Picard, would
do the same thing from the Paris Observatory. The team had to wait nearly a
year to bring their observations together and work out the trigonometry, but,
even with the less precise instruments of the day, they were able to come up
with an estimate for the Mars-Earth distance that was within about 7% of the
modern calculation.
Interestingly enough, John Flamsteed (what is with all these guys named John
or Jean in French obsessing on the same thing?) came up with another approach
to parallax that didn't entail a long and arduous trip. He observed Mars at
two time periods in the same night widely separated in time, so that the
earth's rotation would give him the spatial separation he needed to establish
his baseline. His estimate turned out pretty close to the Cassini team's
estimate.
Your data and methods
Here is an idealized diagram of the parallax situation. You have a triangle
of concern, the one leading from the two places on Earth and Mars, which can
be subdivided into two right triangles (with the hypotenuse, opposite, and
adjacent sides labelled).
What you need to figure out is A, the length of the adjacent side, but
all you
have is O or the baseline of ~3,350 km or one-half the chord distance
of 6,700
km between Paris and Cayenne and the parallax angle, which is 9.5
arcseconds.
First, divide 9.5 by 3,600 (60 seconds times 60 minutes) to get the
parallax angle in
degrees. What would that (extremely tiny number) be?
1. _________________________
You're trying to imagine creating an insanely skinny angle between the adjacent
side and the hypotenuse and then resting
the adjacent side along the straight line from Mars to Earth. If you imagine
sliding a ruler along the length of the adjacent side at right angles to it,
you're trying to move that ruler
just until until the open end of the angle (between H and A) is 3,350 km wide
(the width of the O or opposite
side in your triangle, now formed by your imaginary ruler). How far down the A
side do you have to slide the O
ruler?
From trigonometry come some useful ratios: SOH, CAH, TOA
(sine=opposite/hypotenuse; cosine=alternative/hypotenuse;
tangent=opposite/alternate). We don't care about the hypotenuse, so that gets
rid of the sine and the cosine. We're interested in figuring out the length
of the alternate side from knowing the opposite side (3,350 km), so that
leaves us with the tangent of that very skinny triangle. You need to
convert the angle of that skinny triangle from degrees into tangent form. You
can do that with a calculator (tan function) or, in
Open/LibreOffice Calc, which would be =tan(radians(9.5/3600)) or
=tan(radians(whichever cell you put the degrees calculation in)). So, what
would that tangent be?
2. _________________________
So, now you have two of the three elements of TOA (tangent = opposite divided
by alternate, T = O/A): the tangent and the opposite (3,350 km). But what we
need is the length of the alternate side. So, let's algebraically re-arrange
the formula to A = O/T. Go on ahead and divide O or 3,350 by that
insanely small tangent you just calculated. The answer for A is the Earth-
Mars distance.
3. _________________________
Now that you have the distance between Mars and Earth at opposition on 1
October 1672, you can apply Kepler's Third Law to figure out the Cassini
team's
estimate of the Astronomical Unit, or the distance between the Earth and Sun.
Remember that the ratio formed by the squared periods of the two planets'
years or periods is the same as the ratio formed by the cubes of their
distances from the sun. So, let's calculate the ratio of the squared periods.
Earth's year is 365.25 Earth days long; Mars' year is 686.98 Earth days long
(or 668.60 sols/martian days long). What's the square of Mars' revolutionary
period?
4. _________________________
And what's the square of Earth's period?
5. _________________________
Divide Mars' squared period by Earth's squared period to get that ratio:
6. _________________________
That ratio is the same as the ratio of the cubed radiuses or distances from
the sun to each planet. So, let's now take the cube root of that
ratio between the squared periods.
With a calculator, you'd enter the ratio and then the
x√Y key and then the number 3, then the equals sign.
In a spreadsheet, you would create a reference to the cell where you calculated
that ratio. I'll call
that cell C6 here (use whichever cell you used to calculate that ratio!). In another
cell, you'd type =C6^1/3 or =c6^(1/3) (in a spreadsheet, you raise the number
to the 1/3rd power, which is the same as taking the cube root, which spreadsheets
don't do directly).
So, whichever way you did it, what would that cube root be?
7. __________________________
Now, subtract 1 from cube root of the ratio of the squared Mars and Earth
years. That is?
8. _________________________
Divide the Earth-Mars distance by this answer. That is roughly the Earth-Sun
distance that Cassini, Richer, and Picard figured out, or the Astronomical
Unit. What is their estimate of the au?
9. _________________________
Now, this estimate just blew the astronomical community away. Thanks to
Kepler, they knew the relative distances of the various solar system bodies in
the newly accepted Copernican heliocentric model, but no-one knew what the
actual distance of a single au was. Once the Cassini team (and,
independently, Flamsteed) had that number down, and it was so huge, the true
scale of the solar system dawned on everyone. The solar system was vaster
than anyone had imagined, a realization almost as drastic as the Copernican
rearrangement of everything around the sun.
Given the instruments of the day, imprecision in the distance between Paris
and Cayenne, trying to get two teams observing at exactly midnight their
time, and the slight movement of Mars between the midnight of Paris and the
later midnight of Cayenne, there would have to be large uncertainty
bars around these estimates, but, even so, they got very close to the modern
value for the au, within about 7%, just from sheer logic, imagination, and
meticulous record-keeping.
You might optionally try redoing the whole process with contemporary figures:
- Mars parallax: 8.794143 arcseconds
- one half Paris-Cayenne chord distance 3,340 km
10. _________________________ (optional extra credit)
The current estimate of the astronomical unit is 149,597,870.691 km.